16x^2+31x-12=0

Solution for 16x^2+31x-12=0 equation:

16x^2+31x-12=0

a = 16; b = 31; c = -12;
Δ = b2-4ac
Δ = 312-4·16·(-12)
Δ = 1729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{1729}}{2*16}=\frac{-31-\sqrt{1729}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{1729}}{2*16}=\frac{-31+\sqrt{1729}}{32}
$